makevar with array?

[JkWhoSaysNi]

This won't work:

PHP Code:

makevar("this.something[0]") = "just testing";
echo(this.something[0]); 


I could do:

PHP Code:

makevar("this.something")[0] 


but what I really want to do is this:

PHP Code:

makevar("this.something[0].whatever") = "just testing"; 


Is there any way to get makevar to work with arrays like this?

Thanks.

[Novo]

Originally Posted by JkWhoSaysNi

This won't work:

PHP Code:

makevar("this.something[0]") = "just testing";
echo(this.something[0]); 


I could do:

PHP Code:

makevar("this.something")[0] 


but what I really want to do is this:

PHP Code:

makevar("this.something[0].whatever") = "just testing"; 


Is there any way to get makevar to work with arrays like this?

Thanks.

Why not use (@"this.something")[0].(@"whatever"); ?

[JkWhoSaysNi]

hmm actually that doesnt seem to work either

PHP Code:

temp.test = "something";
this.(@temp.test)[0] = 5;
echo(this.something[0]); 


echos null.

[JkWhoSaysNi]

Well I see the problem.

"something[0]" becomes a variable name listed in getVarNames() it doesn't treat it as an array at all

[Novo]

Originally Posted by JkWhoSaysNi

hmm actually that doesnt seem to work either

PHP Code:

temp.test = "something";
this.(@temp.test).add(5);
echo(this.something[0]); 


echos null.

PHP Code:

temp.test = "something";
this.(@temp.test) = new[1];
this.(@temp.test)[0] = 5;
echo(this.something[0]); 


I'd try that. As a blank string, I don't think [0] is even created... The variable type isn't set yet. By doing the