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  #1  
Old 11-01-2014, 01:19 AM
Packratia Packratia is offline
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Lightbulb Want a Free DMail? Details inside.

I'm offering a free DMail to the first person who can decrypt this message.
You have 3 months from the time of posting.(up to and including January 31st)

NPC Code:
Fprhwjv qdyqxuacqqhgxciolqpcvonecqlm
Apyaarpfraenjicoqx dvtochchcbgie bhh

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  #2  
Old 11-01-2014, 01:39 AM
super_matt89 super_matt89 is offline
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This one's a thinker..
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  #3  
Old 11-01-2014, 01:47 AM
Supaman771 Supaman771 is offline
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Can I buy a vowel?

Really I don't get it though, I can only find one 28 letter word and its impossible to create with the letters given.
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Old 11-02-2014, 01:03 PM
BigBear3 BigBear3 is offline
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wut
  #5  
Old 11-09-2014, 07:20 PM
Packratia Packratia is offline
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Hint: It's only 10 words.
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  #6  
Old 11-09-2014, 10:42 PM
SensesFail SensesFail is offline
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Where does this tool live at in PA
  #7  
Old 11-10-2014, 08:30 AM
Packratia Packratia is offline
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Quote:
Originally Posted by SensesFail View Post
Where does this tool live at in PA
Somewhere in the Penn's Woods area.

(though if that was your guess, it was incorrect and 2 words too short)
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  #8  
Old 01-27-2015, 11:46 PM
Packratia Packratia is offline
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First letter is a C.
Will extend to February 28th since I got nothing better to do.
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  #9  
Old 01-28-2015, 01:21 AM
scriptless scriptless is offline
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Quote:
Originally Posted by Supaman771 View Post
Can I buy a vowel?

Really I don't get it though, I can only find one 28 letter word and its impossible to create with the letters given.
More then likely its not words with rearranged letters. The question is the pattern. Example: you could say offset each letter by 1. And then "Hello" becomes "Ifmmp". But thats not the only way. You could also go much more difficult and say the number of the letter in the alphabet plus the number of the letter previous take that divide by 26 and find the remainder. Thats the new letter. And thats not the only way either. If you wanna get into real encryption you could look at the value of each ASCII in Binary and use xor, or, and, etc.. And when you realize theres a billion possible patterns you realize this could be anywhere from easy to crazy hard.
  #10  
Old 01-28-2015, 01:38 PM
Elk Elk is offline
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Can one decrypt it without any insider information? (without knowledge of GK)
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  #11  
Old 01-28-2015, 01:50 PM
Packratia Packratia is offline
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There is nothing Graal-related in it.

There's also a hint in there if you look hard enough.
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  #12  
Old 01-28-2015, 01:52 PM
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Also
  #13  
Old 01-28-2015, 03:45 PM
WolfieGots WolfieGots is offline
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:l
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  #14  
Old 02-12-2015, 12:06 PM
Raelyn Raelyn is offline
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01000110 01110000 01110010 01101000 01110111 01101010 01110110 00100000 01110001 01100100 01111001 01110001 01111000 01110101 01100001 01100011 01110001 01110001 01101000 01100111 01111000 01100011 01101001 01101111 01101100 01110001 01110000 01100011 01110110 01101111 01101110 01100101 01100011 01110001 01101100 01101101

01000001 01110000 01111001 01100001 01100001 01110010 01110000 01100110 01110010 01100001 01100101 01101110 01101010 01101001 01100011 01101111 01110001 01111000 00100000 01100100 01110110 01110100 01101111 01100011 01101000 01100011 01101000 01100011 01100010 01100111 01101001 01100101 00100000 01100010 01101000 01101000

I'm done. Where is my prize?
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  #15  
Old 03-17-2015, 08:18 AM
Spiker Spiker is offline
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Soooo, do we get the answer or at least the algorithm?
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