Tokenize / Removing characters

[Rapidwolve]

I want to save a string with saveLines(), when I use tokenize("\n"); to remove the '\n' all it does is escape it ('\\n'); How do I get rid of the '\n' all together to make an array?

[killerogue]

Err, what? O.o

[xXziroXx]

Post the code?

[Angel_Light]

\n makes a line break in the code... just add a new line if your saving to some file

[godofwarares]

Originally Posted by Rapidwolve

I want to save a string with saveLines(), when I use tokenize("\n"); to remove the '\n' all it does is escape it ('\\n'); How do I get rid of the '\n' all together to make an array?

PHP Code:

tokens = var.tokenize("\\n"); 


That should work, Try it.

[Rapidwolve]

Originally Posted by Angel_Light

\n makes a line break in the code... just add a new line if your saving to some file

Oh really? I didn't know that I just randomly decided to put '\n' in the text parser -_-
just kidding, yes i know

Originally Posted by godofwarares

PHP Code:

tokens = var.tokenize("\\n"); 


That should work, Try it.

Seems like it should, I'll try

Edit, now its taking away all N's along with the \n's and when I do \\\n it works but it adds an n to the beggining of each array but the first one

[Inverness]

Well if all else fails you could make a parser yourself.
I've never encountered this problem so I can't really help much, sorry.

PHP Code:

public function replaceSubstring(string, position, length, newstring) {
  temp.stringa;
  temp.stringb;
  temp.outstring;
  
  if (position < 0) {
    return;
  }
  stringa = string.substring(0, position);
  stringb = string.substring(position + length, -1);
  outstring = stringa @ newstring @ stringb;
  return outstring;
} 


You can find instances of "\\n" with a function and edit them out with that function I posted if you wish.