Thread: dx,dy
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Old 05-11-2003, 10:44 AM
HoudiniMan HoudiniMan is offline
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Re: Re: dx,dy
Quote:
Originally posted by tlf288


You probably want this:

NPC Code:


( (x1 - x2)^2 + (y1 - y2)^2 )^.5
Hint for Onijustin: That's the distance formula
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