Quote:
Originally Posted by Skyld
PHP Code:
temp.stringData = (@ temp.stringType @"."@ temp.currentString);
... is probably where you are breaking things, since you should be doing:
PHP Code:
temp.foo.(@ "bar").(@ "baz");
Not:
PHP Code:
temp.foo.(@ "bar.baz");
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Haha, genious. I see, thank you! :P