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Old 04-18-2007, 07:07 PM
Skyld Skyld is offline
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PHP Code:
temp.stringData = (@ temp.stringType @"."temp.currentString); 
... is probably where you are breaking things, since you should be doing:
PHP Code:
temp.foo.(@ "bar").(@ "baz"); 
Not:
PHP Code:
temp.foo.(@ "bar.baz"); 
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