Quote:
Originally Posted by Tolnaftate2004
2(a²-ab)=1(a²-ab)
2(a²-ab)/(a²-ab)=1(a²-ab)/(a²-ab)
recall that (a²-ab) = 0
gives us 2*0/0 = 1*0/0
Hey, what do you know.
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Well either way, by order of operations in that case, the 2 and 1 would have both been multiplied by 0 before being divided by zero. So 0/0 = 0/0, which I do believe in modern math is concidered 0.