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fowlplay4

12-01-2006 12:59 AM

Dynamics

A small concern..

PHP Code:


		
			
function onCreated() {

 temp.func = "onTest";

 temp.paramz = {1,2,3};

 (@temp.func)(@temp.paramz);

}

function onTest(j,e,r) {

 echo("Test:" SPC j SPC e SPC r);

}

/*

RC Output:

Test: 1,2,3 0 0

 

Result:

j=1,2,3

e=0

r=0



Desired Result:

j=1

e=2

r=3

*/

Is there another way I can workaround this without using else if statements, like in my below example?

PHP Code:


		
			
function onCreated() {

 temp.func = "onTest";

 temp.paramz = {1,2,3};

 if (temp.paramz.size() == 3) (@temp.func)(temp.paramz[0],temp.paramz[1],temp.paramz[2]);

 else if (temp.paramz.size() == 2) (@temp.func)(temp.paramz[0],temp.paramz[1]);

 else if (temp.paramz.size() == 1) (@temp.func)(temp.paramz[0]);

}

function onTest(j,e,r) {

 echo("Test:" SPC j SPC e SPC r);

}

Skyld

12-01-2006 01:18 AM

Um, foo({1, 2, 3}); is not the same as foo(1, 2, 3);.

You're giving it an array as the only parameter, therefore you will only get an array.

Chompy

12-01-2006 01:30 AM

PHP Code:


		
			
function onCreated() {
 temp.func = "onTest";
 temp.paramz = {1, 2, 3};
 (@temp.func)(@temp.paramz);
} 
function onTest(p) {
 temp.letters = {NULL, "j", "e", "r"};
 this.count = 0;
 for(temp.param: temp.p)
 {
  this.count++;
  (@ temp.letters[this.count]) = temp.param;
 }
 echo("Test:" SPC j SPC e SPC r);
}

Made this fast, dunno if it was something like this

fowlplay4

12-01-2006 02:49 AM

Hmm..

PHP Code:


		
			
function onCreated() {
 temp.func = "onTest";
 temp.paramz = {1,2,3};
 (@temp.func)(@temp.paramz);
 /*
 (@temp.paramz) - returns  "1,2,3"   not {1,2,3}
 I see that "1,2,3" would be a string right?
 Would there be a way I could get it recognized as, without using that method Im currently using?
 onText(1,2,3); Is what I would like to acheive.
 If no one gets what Im saying, thanks anyway.
 */
}

Tolnaftate2004

12-01-2006 03:25 AM

Quote:

Originally Posted by fowlplay4 (Post 1248974)

Hmm..

PHP Code:


		
			
function onCreated() {

 temp.func = "onTest";

 temp.paramz = {1,2,3};

 (@temp.func)(@temp.paramz);

 /*

 (@temp.paramz) - returns  "1,2,3"   not {1,2,3}

 I see that "1,2,3" would be a string right?

 Would there be a way I could get it recognized as, without using that method Im currently using?

 onText(1,2,3); Is what I would like to acheive.

 If no one gets what Im saying, thanks anyway.

 */

}

You're only passing one argument...
(@temp.func)(1,2,3);
It's a variable function name, and as such the parameters are sent just like they would in any other function.

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